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a^2=64a^2=64
We move all terms to the left:
a^2-(64a^2)=0
We add all the numbers together, and all the variables
-63a^2=0
a = -63; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-63)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{0}{-126}=0$
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